11(k-1)=7(k-35)

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Solution for 11(k-1)=7(k-35) equation: 



11(k-1)=7(k-35)

We move all terms to the left:

11(k-1)-(7(k-35))=0

We multiply parentheses

11k-(7(k-35))-11=0



We calculate terms in parentheses: -(7(k-35)), so:

7(k-35)

We multiply parentheses

7k-245

Back to the equation:

-(7k-245)



We get rid of parentheses

11k-7k+245-11=0

We add all the numbers together, and all the variables

4k+234=0

We move all terms containing k to the left, all other terms to the right

4k=-234

k=-234/4

k=-58+1/2

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