11(l-1)-19=3(l+7)+5

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Solution for 11(l-1)-19=3(l+7)+5 equation: 



11(l-1)-19=3(l+7)+5

We move all terms to the left:

11(l-1)-19-(3(l+7)+5)=0

We multiply parentheses

11l-(3(l+7)+5)-11-19=0



We calculate terms in parentheses: -(3(l+7)+5), so:

3(l+7)+5

We multiply parentheses

3l+21+5

We add all the numbers together, and all the variables

3l+26

Back to the equation:

-(3l+26)



We add all the numbers together, and all the variables

11l-(3l+26)-30=0

We get rid of parentheses

11l-3l-26-30=0

We add all the numbers together, and all the variables

8l-56=0

We move all terms containing l to the left, all other terms to the right

8l=56

l=56/8

l=7

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