11(n)+2(n+2)=6(n+4)+1

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Solution for 11(n)+2(n+2)=6(n+4)+1 equation: 



11(n)+2(n+2)=6(n+4)+1

We move all terms to the left:

11(n)+2(n+2)-(6(n+4)+1)=0

We multiply parentheses

11n+2n-(6(n+4)+1)+4=0



We calculate terms in parentheses: -(6(n+4)+1), so:

6(n+4)+1

We multiply parentheses

6n+24+1

We add all the numbers together, and all the variables

6n+25

Back to the equation:

-(6n+25)



We add all the numbers together, and all the variables

13n-(6n+25)+4=0

We get rid of parentheses

13n-6n-25+4=0

We add all the numbers together, and all the variables

7n-21=0

We move all terms containing n to the left, all other terms to the right

7n=21

n=21/7

n=3

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