11(n+5)=4(15+3n)

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Solution for 11(n+5)=4(15+3n) equation: 



11(n+5)=4(15+3n)

We move all terms to the left:

11(n+5)-(4(15+3n))=0

We add all the numbers together, and all the variables

11(n+5)-(4(3n+15))=0

We multiply parentheses

11n-(4(3n+15))+55=0



We calculate terms in parentheses: -(4(3n+15)), so:

4(3n+15)

We multiply parentheses

12n+60

Back to the equation:

-(12n+60)



We get rid of parentheses

11n-12n-60+55=0

We add all the numbers together, and all the variables

-1n-5=0

We move all terms containing n to the left, all other terms to the right

-n=5

n=5/-1

n=-5

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