11(n-10)=-3(n+4)

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Solution for 11(n-10)=-3(n+4) equation: 



11(n-10)=-3(n+4)

We move all terms to the left:

11(n-10)-(-3(n+4))=0

We multiply parentheses

11n-(-3(n+4))-110=0



We calculate terms in parentheses: -(-3(n+4)), so:

-3(n+4)

We multiply parentheses

-3n-12

Back to the equation:

-(-3n-12)



We get rid of parentheses

11n+3n+12-110=0

We add all the numbers together, and all the variables

14n-98=0

We move all terms containing n to the left, all other terms to the right

14n=98

n=98/14

n=7

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