11(s-2)-21=3(s+2)+31

Solution for 11(s-2)-21=3(s+2)+31 equation:

11(s-2)-21=3(s+2)+31

We move all terms to the left:

11(s-2)-21-(3(s+2)+31)=0

We multiply parentheses

11s-(3(s+2)+31)-22-21=0


We calculate terms in parentheses: -(3(s+2)+31), so:

3(s+2)+31

We multiply parentheses

3s+6+31

We add all the numbers together, and all the variables

3s+37

Back to the equation:

-(3s+37)


We add all the numbers together, and all the variables

11s-(3s+37)-43=0

We get rid of parentheses

11s-3s-37-43=0

We add all the numbers together, and all the variables

8s-80=0

We move all terms containing s to the left, all other terms to the right

8s=80

s=80/8

s=10