11(t-2)+3t=7(2t+5)-10

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Solution for 11(t-2)+3t=7(2t+5)-10 equation:


Simplifying
11(t + -2) + 3t = 7(2t + 5) + -10

Reorder the terms:
11(-2 + t) + 3t = 7(2t + 5) + -10
(-2 * 11 + t * 11) + 3t = 7(2t + 5) + -10
(-22 + 11t) + 3t = 7(2t + 5) + -10

Combine like terms: 11t + 3t = 14t
-22 + 14t = 7(2t + 5) + -10

Reorder the terms:
-22 + 14t = 7(5 + 2t) + -10
-22 + 14t = (5 * 7 + 2t * 7) + -10
-22 + 14t = (35 + 14t) + -10

Reorder the terms:
-22 + 14t = 35 + -10 + 14t

Combine like terms: 35 + -10 = 25
-22 + 14t = 25 + 14t

Add '-14t' to each side of the equation.
-22 + 14t + -14t = 25 + 14t + -14t

Combine like terms: 14t + -14t = 0
-22 + 0 = 25 + 14t + -14t
-22 = 25 + 14t + -14t

Combine like terms: 14t + -14t = 0
-22 = 25 + 0
-22 = 25

Solving
-22 = 25

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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