11(t-3)+3t=7(2t+2)-10

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Solution for 11(t-3)+3t=7(2t+2)-10 equation: 



11(t-3)+3t=7(2t+2)-10

We move all terms to the left:

11(t-3)+3t-(7(2t+2)-10)=0

We add all the numbers together, and all the variables

3t+11(t-3)-(7(2t+2)-10)=0

We multiply parentheses

3t+11t-(7(2t+2)-10)-33=0



We calculate terms in parentheses: -(7(2t+2)-10), so:

7(2t+2)-10

We multiply parentheses

14t+14-10

We add all the numbers together, and all the variables

14t+4

Back to the equation:

-(14t+4)



We add all the numbers together, and all the variables

14t-(14t+4)-33=0

We get rid of parentheses

14t-14t-4-33=0

We add all the numbers together, and all the variables

-37!=0

There is no solution for this equation

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