11(u+1)+19=3(u-11)-1

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Solution for 11(u+1)+19=3(u-11)-1 equation: 



11(u+1)+19=3(u-11)-1

We move all terms to the left:

11(u+1)+19-(3(u-11)-1)=0

We multiply parentheses

11u-(3(u-11)-1)+11+19=0



We calculate terms in parentheses: -(3(u-11)-1), so:

3(u-11)-1

We multiply parentheses

3u-33-1

We add all the numbers together, and all the variables

3u-34

Back to the equation:

-(3u-34)



We add all the numbers together, and all the variables

11u-(3u-34)+30=0

We get rid of parentheses

11u-3u+34+30=0

We add all the numbers together, and all the variables

8u+64=0

We move all terms containing u to the left, all other terms to the right

8u=-64

u=-64/8

u=-8

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