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11(x+3)=5(3x+1)
We move all terms to the left:
11(x+3)-(5(3x+1))=0
We multiply parentheses
11x-(5(3x+1))+33=0
We calculate terms in parentheses: -(5(3x+1)), so:We get rid of parentheses
5(3x+1)
We multiply parentheses
15x+5
Back to the equation:
-(15x+5)
11x-15x-5+33=0
We add all the numbers together, and all the variables
-4x+28=0
We move all terms containing x to the left, all other terms to the right
-4x=-28
x=-28/-4
x=+7
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