11(x+4)-2(x-3)=4(x-4)+4(x-3)

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Solution for 11(x+4)-2(x-3)=4(x-4)+4(x-3) equation: 



11(x+4)-2(x-3)=4(x-4)+4(x-3)

We move all terms to the left:

11(x+4)-2(x-3)-(4(x-4)+4(x-3))=0

We multiply parentheses

11x-2x-(4(x-4)+4(x-3))+44+6=0



We calculate terms in parentheses: -(4(x-4)+4(x-3)), so:

4(x-4)+4(x-3)

We multiply parentheses

4x+4x-16-12

We add all the numbers together, and all the variables

8x-28

Back to the equation:

-(8x-28)



We add all the numbers together, and all the variables

9x-(8x-28)+50=0

We get rid of parentheses

9x-8x+28+50=0

We add all the numbers together, and all the variables

x+78=0

We move all terms containing x to the left, all other terms to the right

x=-78

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