11(x+4)-4(x+3)=12(x-3)

Solution for 11(x+4)-4(x+3)=12(x-3) equation:

11(x+4)-4(x+3)=12(x-3)

We move all terms to the left:

11(x+4)-4(x+3)-(12(x-3))=0

We multiply parentheses

11x-4x-(12(x-3))+44-12=0


We calculate terms in parentheses: -(12(x-3)), so:

12(x-3)

We multiply parentheses

12x-36

Back to the equation:

-(12x-36)


We add all the numbers together, and all the variables

7x-(12x-36)+32=0

We get rid of parentheses

7x-12x+36+32=0

We add all the numbers together, and all the variables

-5x+68=0

We move all terms containing x to the left, all other terms to the right

-5x=-68

x=-68/-5

x=13+3/5