11(x+4)-4(x+3)=12(x-3)

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Solution for 11(x+4)-4(x+3)=12(x-3) equation:



11(x+4)-4(x+3)=12(x-3)
We move all terms to the left:
11(x+4)-4(x+3)-(12(x-3))=0
We multiply parentheses
11x-4x-(12(x-3))+44-12=0
We calculate terms in parentheses: -(12(x-3)), so:
12(x-3)
We multiply parentheses
12x-36
Back to the equation:
-(12x-36)
We add all the numbers together, and all the variables
7x-(12x-36)+32=0
We get rid of parentheses
7x-12x+36+32=0
We add all the numbers together, and all the variables
-5x+68=0
We move all terms containing x to the left, all other terms to the right
-5x=-68
x=-68/-5
x=13+3/5

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