11(x+4)-4(x-2)=3(x-2)+3(x-2)

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Solution for 11(x+4)-4(x-2)=3(x-2)+3(x-2) equation: 



11(x+4)-4(x-2)=3(x-2)+3(x-2)

We move all terms to the left:

11(x+4)-4(x-2)-(3(x-2)+3(x-2))=0

We multiply parentheses

11x-4x-(3(x-2)+3(x-2))+44+8=0



We calculate terms in parentheses: -(3(x-2)+3(x-2)), so:

3(x-2)+3(x-2)

We multiply parentheses

3x+3x-6-6

We add all the numbers together, and all the variables

6x-12

Back to the equation:

-(6x-12)



We add all the numbers together, and all the variables

7x-(6x-12)+52=0

We get rid of parentheses

7x-6x+12+52=0

We add all the numbers together, and all the variables

x+64=0

We move all terms containing x to the left, all other terms to the right

x=-64

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