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11(x-1)-3(3x+2)=7(4-x)
We move all terms to the left:
11(x-1)-3(3x+2)-(7(4-x))=0
We add all the numbers together, and all the variables
11(x-1)-3(3x+2)-(7(-1x+4))=0
We multiply parentheses
11x-9x-(7(-1x+4))-11-6=0
We calculate terms in parentheses: -(7(-1x+4)), so:We add all the numbers together, and all the variables
7(-1x+4)
We multiply parentheses
-7x+28
Back to the equation:
-(-7x+28)
2x-(-7x+28)-17=0
We get rid of parentheses
2x+7x-28-17=0
We add all the numbers together, and all the variables
9x-45=0
We move all terms containing x to the left, all other terms to the right
9x=45
x=45/9
x=5
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