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11(x-5)=10x(x+5)
We move all terms to the left:
11(x-5)-(10x(x+5))=0
We multiply parentheses
11x-(10x(x+5))-55=0
We calculate terms in parentheses: -(10x(x+5)), so:We get rid of parentheses
10x(x+5)
We multiply parentheses
10x^2+50x
Back to the equation:
-(10x^2+50x)
-10x^2+11x-50x-55=0
We add all the numbers together, and all the variables
-10x^2-39x-55=0
a = -10; b = -39; c = -55;
Δ = b2-4ac
Δ = -392-4·(-10)·(-55)
Δ = -679
Delta is less than zero, so there is no solution for the equation
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