11(y+2)=5(y-10)+18

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Solution for 11(y+2)=5(y-10)+18 equation: 



11(y+2)=5(y-10)+18

We move all terms to the left:

11(y+2)-(5(y-10)+18)=0

We multiply parentheses

11y-(5(y-10)+18)+22=0



We calculate terms in parentheses: -(5(y-10)+18), so:

5(y-10)+18

We multiply parentheses

5y-50+18

We add all the numbers together, and all the variables

5y-32

Back to the equation:

-(5y-32)



We get rid of parentheses

11y-5y+32+22=0

We add all the numbers together, and all the variables

6y+54=0

We move all terms containing y to the left, all other terms to the right

6y=-54

y=-54/6

y=-9

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