11(y-2)+3y=7y+14

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Solution for 11(y-2)+3y=7y+14 equation:



11(y-2)+3y=7y+14
We move all terms to the left:
11(y-2)+3y-(7y+14)=0
We add all the numbers together, and all the variables
3y+11(y-2)-(7y+14)=0
We multiply parentheses
3y+11y-(7y+14)-22=0
We get rid of parentheses
3y+11y-7y-14-22=0
We add all the numbers together, and all the variables
7y-36=0
We move all terms containing y to the left, all other terms to the right
7y=36
y=36/7
y=5+1/7

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