11(z+1)-2(z-1)=5(z-2)+3(z-1)

Solution for 11(z+1)-2(z-1)=5(z-2)+3(z-1) equation:

11(z+1)-2(z-1)=5(z-2)+3(z-1)

We move all terms to the left:

11(z+1)-2(z-1)-(5(z-2)+3(z-1))=0

We multiply parentheses

11z-2z-(5(z-2)+3(z-1))+11+2=0


We calculate terms in parentheses: -(5(z-2)+3(z-1)), so:

5(z-2)+3(z-1)

We multiply parentheses

5z+3z-10-3

We add all the numbers together, and all the variables

8z-13

Back to the equation:

-(8z-13)


We add all the numbers together, and all the variables

9z-(8z-13)+13=0

We get rid of parentheses

9z-8z+13+13=0

We add all the numbers together, and all the variables

z+26=0

We move all terms containing z to the left, all other terms to the right

z=-26