11(z+1)-4(z-3)=3(z-1)+3(z-1)

Solution for 11(z+1)-4(z-3)=3(z-1)+3(z-1) equation:

11(z+1)-4(z-3)=3(z-1)+3(z-1)

We simplify the equation to the form, which is simple to understand 
11(z+1)-4(z-3)=3(z-1)+3(z-1)

Reorder the terms in parentheses
+(+11z+11)-4*(z-3)=3*(z-1)+3*(z-1)

Remove unnecessary parentheses
+11z+11-4+*(+z-3+)=+3+*(+z-1+)+3+*(+z-1+)

Reorder the terms in parentheses
+11z+11+(-4z+12)=3*(z-1)+3*(z-1)

Remove unnecessary parentheses
+11z+11-4z+12=+3+*(+z-1+)+3+*(+z-1+)

Reorder the terms in parentheses
+11z+11-4z+12=+(+3z-3)+3*(z-1)

Remove unnecessary parentheses
+11z+11-4z+12=+3z-3+3+*(+z-1+)

Reorder the terms in parentheses
+11z+11-4z+12=+3z-3+(+3z-3)

Remove unnecessary parentheses
+11z+11-4z+12=+3z-3+3z-3

We move all terms containing z to the left and all other terms to the right. 
+11z-4z-3z-3z=-3-3-11-12

We simplify left and right side of the equation. 
+1z=-29

We divide both sides of the equation by 1 to get z. 
z=-29