11(z+2)-2(z-3)=4(z-3)+4(z-4)

Solution for 11(z+2)-2(z-3)=4(z-3)+4(z-4) equation:

Simplifying
11(z + 2) + -2(z + -3) = 4(z + -3) + 4(z + -4)

Reorder the terms:
11(2 + z) + -2(z + -3) = 4(z + -3) + 4(z + -4)
(2 * 11 + z * 11) + -2(z + -3) = 4(z + -3) + 4(z + -4)
(22 + 11z) + -2(z + -3) = 4(z + -3) + 4(z + -4)

Reorder the terms:
22 + 11z + -2(-3 + z) = 4(z + -3) + 4(z + -4)
22 + 11z + (-3 * -2 + z * -2) = 4(z + -3) + 4(z + -4)
22 + 11z + (6 + -2z) = 4(z + -3) + 4(z + -4)

Reorder the terms:
22 + 6 + 11z + -2z = 4(z + -3) + 4(z + -4)

Combine like terms: 22 + 6 = 28
28 + 11z + -2z = 4(z + -3) + 4(z + -4)

Combine like terms: 11z + -2z = 9z
28 + 9z = 4(z + -3) + 4(z + -4)

Reorder the terms:
28 + 9z = 4(-3 + z) + 4(z + -4)
28 + 9z = (-3 * 4 + z * 4) + 4(z + -4)
28 + 9z = (-12 + 4z) + 4(z + -4)

Reorder the terms:
28 + 9z = -12 + 4z + 4(-4 + z)
28 + 9z = -12 + 4z + (-4 * 4 + z * 4)
28 + 9z = -12 + 4z + (-16 + 4z)

Reorder the terms:
28 + 9z = -12 + -16 + 4z + 4z

Combine like terms: -12 + -16 = -28
28 + 9z = -28 + 4z + 4z

Combine like terms: 4z + 4z = 8z
28 + 9z = -28 + 8z

Solving
28 + 9z = -28 + 8z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-8z' to each side of the equation.
28 + 9z + -8z = -28 + 8z + -8z

Combine like terms: 9z + -8z = 1z
28 + 1z = -28 + 8z + -8z

Combine like terms: 8z + -8z = 0
28 + 1z = -28 + 0
28 + 1z = -28

Add '-28' to each side of the equation.
28 + -28 + 1z = -28 + -28

Combine like terms: 28 + -28 = 0
0 + 1z = -28 + -28
1z = -28 + -28

Combine like terms: -28 + -28 = -56
1z = -56

Divide each side by '1'.
z = -56

Simplifying
z = -56