11(z+2)-3(z-3)=4(z-3)+3(z-1)

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Solution for 11(z+2)-3(z-3)=4(z-3)+3(z-1) equation:


11(z+2)-3(z-3)=4(z-3)+3(z-1)

We simplify the equation to the form, which is simple to understand 
11(z+2)-3(z-3)=4(z-3)+3(z-1)

Reorder the terms in parentheses
+(+11z+22)-3*(z-3)=4*(z-3)+3*(z-1)

Remove unnecessary parentheses
+11z+22-3+*(+z-3+)=+4+*(+z-3+)+3+*(+z-1+)

Reorder the terms in parentheses
+11z+22+(-3z+9)=4*(z-3)+3*(z-1)

Remove unnecessary parentheses
+11z+22-3z+9=+4+*(+z-3+)+3+*(+z-1+)

Reorder the terms in parentheses
+11z+22-3z+9=+(+4z-12)+3*(z-1)

Remove unnecessary parentheses
+11z+22-3z+9=+4z-12+3+*(+z-1+)

Reorder the terms in parentheses
+11z+22-3z+9=+4z-12+(+3z-3)

Remove unnecessary parentheses
+11z+22-3z+9=+4z-12+3z-3

We move all terms containing z to the left and all other terms to the right. 
+11z-3z-4z-3z=-12-3-22-9

We simplify left and right side of the equation. 
+1z=-46

We divide both sides of the equation by 1 to get z. 
z=-46

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