11(z+2)=2(z+6)-13

Solution for 11(z+2)=2(z+6)-13 equation:

11(z+2)=2(z+6)-13

We move all terms to the left:

11(z+2)-(2(z+6)-13)=0

We multiply parentheses

11z-(2(z+6)-13)+22=0


We calculate terms in parentheses: -(2(z+6)-13), so:

2(z+6)-13

We multiply parentheses

2z+12-13

We add all the numbers together, and all the variables

2z-1

Back to the equation:

-(2z-1)


We get rid of parentheses

11z-2z+1+22=0

We add all the numbers together, and all the variables

9z+23=0

We move all terms containing z to the left, all other terms to the right

9z=-23

z=-23/9

z=-2+5/9