11(z+3)-3(z-1)=4(z-1)+3(z-2)

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Solution for 11(z+3)-3(z-1)=4(z-1)+3(z-2) equation: 



11(z+3)-3(z-1)=4(z-1)+3(z-2)

We move all terms to the left:

11(z+3)-3(z-1)-(4(z-1)+3(z-2))=0

We multiply parentheses

11z-3z-(4(z-1)+3(z-2))+33+3=0



We calculate terms in parentheses: -(4(z-1)+3(z-2)), so:

4(z-1)+3(z-2)

We multiply parentheses

4z+3z-4-6

We add all the numbers together, and all the variables

7z-10

Back to the equation:

-(7z-10)



We add all the numbers together, and all the variables

8z-(7z-10)+36=0

We get rid of parentheses

8z-7z+10+36=0

We add all the numbers together, and all the variables

z+46=0

We move all terms containing z to the left, all other terms to the right

z=-46

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