11(z+3)-4(z-1)=3(z-1)+3(z-2)

Solution for 11(z+3)-4(z-1)=3(z-1)+3(z-2) equation:

11(z+3)-4(z-1)=3(z-1)+3(z-2)

We move all terms to the left:

11(z+3)-4(z-1)-(3(z-1)+3(z-2))=0

We multiply parentheses

11z-4z-(3(z-1)+3(z-2))+33+4=0


We calculate terms in parentheses: -(3(z-1)+3(z-2)), so:

3(z-1)+3(z-2)

We multiply parentheses

3z+3z-3-6

We add all the numbers together, and all the variables

6z-9

Back to the equation:

-(6z-9)


We add all the numbers together, and all the variables

7z-(6z-9)+37=0

We get rid of parentheses

7z-6z+9+37=0

We add all the numbers together, and all the variables

z+46=0

We move all terms containing z to the left, all other terms to the right

z=-46