11(z+4)-2(z-2)=4(z-1)+4(z-2)

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Solution for 11(z+4)-2(z-2)=4(z-1)+4(z-2) equation:



11(z+4)-2(z-2)=4(z-1)+4(z-2)
We move all terms to the left:
11(z+4)-2(z-2)-(4(z-1)+4(z-2))=0
We multiply parentheses
11z-2z-(4(z-1)+4(z-2))+44+4=0
We calculate terms in parentheses: -(4(z-1)+4(z-2)), so:
4(z-1)+4(z-2)
We multiply parentheses
4z+4z-4-8
We add all the numbers together, and all the variables
8z-12
Back to the equation:
-(8z-12)
We add all the numbers together, and all the variables
9z-(8z-12)+48=0
We get rid of parentheses
9z-8z+12+48=0
We add all the numbers together, and all the variables
z+60=0
We move all terms containing z to the left, all other terms to the right
z=-60

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