11(z+4)-3(z-1)=4(z-1)+3(z-1)

Solution for 11(z+4)-3(z-1)=4(z-1)+3(z-1) equation:

11(z+4)-3(z-1)=4(z-1)+3(z-1)

We move all terms to the left:

11(z+4)-3(z-1)-(4(z-1)+3(z-1))=0

We multiply parentheses

11z-3z-(4(z-1)+3(z-1))+44+3=0


We calculate terms in parentheses: -(4(z-1)+3(z-1)), so:

4(z-1)+3(z-1)

We multiply parentheses

4z+3z-4-3

We add all the numbers together, and all the variables

7z-7

Back to the equation:

-(7z-7)


We add all the numbers together, and all the variables

8z-(7z-7)+47=0

We get rid of parentheses

8z-7z+7+47=0

We add all the numbers together, and all the variables

z+54=0

We move all terms containing z to the left, all other terms to the right

z=-54