11(z+4)-4(z-3)=4(Z-1)+2(z-1)

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Solution for 11(z+4)-4(z-3)=4(Z-1)+2(z-1) equation:


11(z+4)-4(z-3)=4(z-1)+2(z-1)

We simplify the equation to the form, which is simple to understand 
11(z+4)-4(z-3)=4(z-1)+2(z-1)

Reorder the terms in parentheses
+(+11z+44)-4*(z-3)=4*(z-1)+2*(z-1)

Remove unnecessary parentheses
+11z+44-4+*(+z-3+)=+4+*(+z-1+)+2+*(+z-1+)

Reorder the terms in parentheses
+11z+44+(-4z+12)=4*(z-1)+2*(z-1)

Remove unnecessary parentheses
+11z+44-4z+12=+4+*(+z-1+)+2+*(+z-1+)

Reorder the terms in parentheses
+11z+44-4z+12=+(+4z-4)+2*(z-1)

Remove unnecessary parentheses
+11z+44-4z+12=+4z-4+2+*(+z-1+)

Reorder the terms in parentheses
+11z+44-4z+12=+4z-4+(+2z-2)

Remove unnecessary parentheses
+11z+44-4z+12=+4z-4+2z-2

We move all terms containing z to the left and all other terms to the right. 
+11z-4z-4z-2z=-4-2-44-12

We simplify left and right side of the equation. 
+1z=-62

We divide both sides of the equation by 1 to get z. 
z=-62

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