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11+1/3x=1/x
We move all terms to the left:
11+1/3x-(1/x)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1/3x-(+1/x)+11=0
We get rid of parentheses
1/3x-1/x+11=0
We calculate fractions
x/3x^2+(-3x)/3x^2+11=0
We multiply all the terms by the denominator
x+(-3x)+11*3x^2=0
Wy multiply elements
33x^2+x+(-3x)=0
We get rid of parentheses
33x^2+x-3x=0
We add all the numbers together, and all the variables
33x^2-2x=0
a = 33; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·33·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*33}=\frac{0}{66} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*33}=\frac{4}{66} =2/33 $
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