11+2b=3(2+b)

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Solution for 11+2b=3(2+b) equation: 



11+2b=3(2+b)

We move all terms to the left:

11+2b-(3(2+b))=0

We add all the numbers together, and all the variables

2b-(3(b+2))+11=0



We calculate terms in parentheses: -(3(b+2)), so:

3(b+2)

We multiply parentheses

3b+6

Back to the equation:

-(3b+6)



We get rid of parentheses

2b-3b-6+11=0

We add all the numbers together, and all the variables

-1b+5=0

We move all terms containing b to the left, all other terms to the right

-b=-5

b=-5/-1

b=+5

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