11+3(r-7)=16-(r+2)

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Solution for 11+3(r-7)=16-(r+2) equation: 



11+3(r-7)=16-(r+2)

We move all terms to the left:

11+3(r-7)-(16-(r+2))=0

We multiply parentheses

3r-(16-(r+2))-21+11=0



We calculate terms in parentheses: -(16-(r+2)), so:

16-(r+2)

determiningTheFunctionDomain
-(r+2)+16

We get rid of parentheses

-r-2+16

We add all the numbers together, and all the variables

-1r+14

Back to the equation:

-(-1r+14)



We add all the numbers together, and all the variables

3r-(-1r+14)-10=0

We get rid of parentheses

3r+1r-14-10=0

We add all the numbers together, and all the variables

4r-24=0

We move all terms containing r to the left, all other terms to the right

4r=24

r=24/4

r=6

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