11+3x=3x-2(7-2x)

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Solution for 11+3x=3x-2(7-2x) equation: 



11+3x=3x-2(7-2x)

We move all terms to the left:

11+3x-(3x-2(7-2x))=0

We add all the numbers together, and all the variables

3x-(3x-2(-2x+7))+11=0



We calculate terms in parentheses: -(3x-2(-2x+7)), so:

3x-2(-2x+7)

We multiply parentheses

3x+4x-14

We add all the numbers together, and all the variables

7x-14

Back to the equation:

-(7x-14)



We get rid of parentheses

3x-7x+14+11=0

We add all the numbers together, and all the variables

-4x+25=0

We move all terms containing x to the left, all other terms to the right

-4x=-25

x=-25/-4

x=6+1/4

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