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11+4(x-3)=13-3(x+2)
We move all terms to the left:
11+4(x-3)-(13-3(x+2))=0
We multiply parentheses
4x-(13-3(x+2))-12+11=0
We calculate terms in parentheses: -(13-3(x+2)), so:We add all the numbers together, and all the variables
13-3(x+2)
determiningTheFunctionDomain -3(x+2)+13
We multiply parentheses
-3x-6+13
We add all the numbers together, and all the variables
-3x+7
Back to the equation:
-(-3x+7)
4x-(-3x+7)-1=0
We get rid of parentheses
4x+3x-7-1=0
We add all the numbers together, and all the variables
7x-8=0
We move all terms containing x to the left, all other terms to the right
7x=8
x=8/7
x=1+1/7
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