11+6b+3=6(b+2)-(b+1)

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Solution for 11+6b+3=6(b+2)-(b+1) equation: 



11+6b+3=6(b+2)-(b+1)

We move all terms to the left:

11+6b+3-(6(b+2)-(b+1))=0

We add all the numbers together, and all the variables

6b-(6(b+2)-(b+1))+14=0



We calculate terms in parentheses: -(6(b+2)-(b+1)), so:

6(b+2)-(b+1)

We multiply parentheses

6b-(b+1)+12

We get rid of parentheses

6b-b-1+12

We add all the numbers together, and all the variables

5b+11

Back to the equation:

-(5b+11)



We get rid of parentheses

6b-5b-11+14=0

We add all the numbers together, and all the variables

b+3=0

We move all terms containing b to the left, all other terms to the right

b=-3

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