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11+x=-2x+(3+2x)
We move all terms to the left:
11+x-(-2x+(3+2x))=0
We add all the numbers together, and all the variables
x-(-2x+(2x+3))+11=0
We calculate terms in parentheses: -(-2x+(2x+3)), so:We add all the numbers together, and all the variables
-2x+(2x+3)
We get rid of parentheses
-2x+2x+3
We add all the numbers together, and all the variables
3
Back to the equation:
-(3)
x+8=0
We move all terms containing x to the left, all other terms to the right
x=-8
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