11-(2x+3)=4(x+5)

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Solution for 11-(2x+3)=4(x+5) equation:



11-(2x+3)=4(x+5)
We move all terms to the left:
11-(2x+3)-(4(x+5))=0
We get rid of parentheses
-2x-(4(x+5))-3+11=0
We calculate terms in parentheses: -(4(x+5)), so:
4(x+5)
We multiply parentheses
4x+20
Back to the equation:
-(4x+20)
We add all the numbers together, and all the variables
-2x-(4x+20)+8=0
We get rid of parentheses
-2x-4x-20+8=0
We add all the numbers together, and all the variables
-6x-12=0
We move all terms containing x to the left, all other terms to the right
-6x=12
x=12/-6
x=-2

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