11-(3k+10)+4K=3(2k+1)-11

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Solution for 11-(3k+10)+4K=3(2k+1)-11 equation: 



11-(3k+10)+4=3(2k+1)-11

We move all terms to the left:

11-(3k+10)+4-(3(2k+1)-11)=0

We add all the numbers together, and all the variables

-(3k+10)-(3(2k+1)-11)+15=0

We get rid of parentheses

-3k-(3(2k+1)-11)-10+15=0



We calculate terms in parentheses: -(3(2k+1)-11), so:

3(2k+1)-11

We multiply parentheses

6k+3-11

We add all the numbers together, and all the variables

6k-8

Back to the equation:

-(6k-8)



We add all the numbers together, and all the variables

-3k-(6k-8)+5=0

We get rid of parentheses

-3k-6k+8+5=0

We add all the numbers together, and all the variables

-9k+13=0

We move all terms containing k to the left, all other terms to the right

-9k=-13

k=-13/-9

k=1+4/9

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