11-2(+-3)=5(2t+1)-6(t+3)

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Solution for 11-2(+-3)=5(2t+1)-6(t+3) equation: 



11-2(+-3)=5(2t+1)-6(t+3)

We move all terms to the left:

11-2(+-3)-(5(2t+1)-6(t+3))=0

We add all the numbers together, and all the variables

-(5(2t+1)-6(t+3))+11-2(-3)=0

We add all the numbers together, and all the variables

-(5(2t+1)-6(t+3))+17=0



We calculate terms in parentheses: -(5(2t+1)-6(t+3)), so:

5(2t+1)-6(t+3)

We multiply parentheses

10t-6t+5-18

We add all the numbers together, and all the variables

4t-13

Back to the equation:

-(4t-13)



We get rid of parentheses

-4t+13+17=0

We add all the numbers together, and all the variables

-4t+30=0

We move all terms containing t to the left, all other terms to the right

-4t=-30

t=-30/-4

t=7+1/2

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