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11-2(1-x)-(x+1)=x-(x-1)+12
We move all terms to the left:
11-2(1-x)-(x+1)-(x-(x-1)+12)=0
We add all the numbers together, and all the variables
-2(-1x+1)-(x+1)-(x-(x-1)+12)+11=0
We multiply parentheses
2x-(x+1)-(x-(x-1)+12)-2+11=0
We get rid of parentheses
2x-x-(x-(x-1)+12)-1-2+11=0
We calculate terms in parentheses: -(x-(x-1)+12), so:We add all the numbers together, and all the variables
x-(x-1)+12
We get rid of parentheses
x-x+1+12
We add all the numbers together, and all the variables
13
Back to the equation:
-(13)
x-5=0
We move all terms containing x to the left, all other terms to the right
x=5
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