11-2(3b-10)=5(4-b)

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Solution for 11-2(3b-10)=5(4-b) equation: 



11-2(3b-10)=5(4-b)

We move all terms to the left:

11-2(3b-10)-(5(4-b))=0

We add all the numbers together, and all the variables

-2(3b-10)-(5(-1b+4))+11=0

We multiply parentheses

-6b-(5(-1b+4))+20+11=0



We calculate terms in parentheses: -(5(-1b+4)), so:

5(-1b+4)

We multiply parentheses

-5b+20

Back to the equation:

-(-5b+20)



We add all the numbers together, and all the variables

-6b-(-5b+20)+31=0

We get rid of parentheses

-6b+5b-20+31=0

We add all the numbers together, and all the variables

-1b+11=0

We move all terms containing b to the left, all other terms to the right

-b=-11

b=-11/-1

b=+11

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