11-2(3y+1)=5(4+y)

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Solution for 11-2(3y+1)=5(4+y) equation: 



11-2(3y+1)=5(4+y)

We move all terms to the left:

11-2(3y+1)-(5(4+y))=0

We add all the numbers together, and all the variables

-2(3y+1)-(5(y+4))+11=0

We multiply parentheses

-6y-(5(y+4))-2+11=0



We calculate terms in parentheses: -(5(y+4)), so:

5(y+4)

We multiply parentheses

5y+20

Back to the equation:

-(5y+20)



We add all the numbers together, and all the variables

-6y-(5y+20)+9=0

We get rid of parentheses

-6y-5y-20+9=0

We add all the numbers together, and all the variables

-11y-11=0

We move all terms containing y to the left, all other terms to the right

-11y=11

y=11/-11

y=-1

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