11-2(s-5)=7(s-3)

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Solution for 11-2(s-5)=7(s-3) equation: 



11-2(s-5)=7(s-3)

We move all terms to the left:

11-2(s-5)-(7(s-3))=0

We multiply parentheses

-2s-(7(s-3))+10+11=0



We calculate terms in parentheses: -(7(s-3)), so:

7(s-3)

We multiply parentheses

7s-21

Back to the equation:

-(7s-21)



We add all the numbers together, and all the variables

-2s-(7s-21)+21=0

We get rid of parentheses

-2s-7s+21+21=0

We add all the numbers together, and all the variables

-9s+42=0

We move all terms containing s to the left, all other terms to the right

-9s=-42

s=-42/-9

s=4+2/3

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