11-2(x-5)=7(x+3)

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Solution for 11-2(x-5)=7(x+3) equation: 



11-2(x-5)=7(x+3)

We move all terms to the left:

11-2(x-5)-(7(x+3))=0

We multiply parentheses

-2x-(7(x+3))+10+11=0



We calculate terms in parentheses: -(7(x+3)), so:

7(x+3)

We multiply parentheses

7x+21

Back to the equation:

-(7x+21)



We add all the numbers together, and all the variables

-2x-(7x+21)+21=0

We get rid of parentheses

-2x-7x-21+21=0

We add all the numbers together, and all the variables

-9x=0

x=0/-9

x=0

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