11-2(y-4)=5(y+1)

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Solution for 11-2(y-4)=5(y+1) equation:



11-2(y-4)=5(y+1)
We move all terms to the left:
11-2(y-4)-(5(y+1))=0
We multiply parentheses
-2y-(5(y+1))+8+11=0
We calculate terms in parentheses: -(5(y+1)), so:
5(y+1)
We multiply parentheses
5y+5
Back to the equation:
-(5y+5)
We add all the numbers together, and all the variables
-2y-(5y+5)+19=0
We get rid of parentheses
-2y-5y-5+19=0
We add all the numbers together, and all the variables
-7y+14=0
We move all terms containing y to the left, all other terms to the right
-7y=-14
y=-14/-7
y=+2

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