11-3(q+2)-2(1-2q)=4(q+2)-1

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Solution for 11-3(q+2)-2(1-2q)=4(q+2)-1 equation: 



11-3(q+2)-2(1-2q)=4(q+2)-1

We move all terms to the left:

11-3(q+2)-2(1-2q)-(4(q+2)-1)=0

We add all the numbers together, and all the variables

-3(q+2)-2(-2q+1)-(4(q+2)-1)+11=0

We multiply parentheses

-3q+4q-(4(q+2)-1)-6-2+11=0



We calculate terms in parentheses: -(4(q+2)-1), so:

4(q+2)-1

We multiply parentheses

4q+8-1

We add all the numbers together, and all the variables

4q+7

Back to the equation:

-(4q+7)



We add all the numbers together, and all the variables

q-(4q+7)+3=0

We get rid of parentheses

q-4q-7+3=0

We add all the numbers together, and all the variables

-3q-4=0

We move all terms containing q to the left, all other terms to the right

-3q=4

q=4/-3

q=-1+1/3

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