11-3(x+4)+5=-3(x+4)+16

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Solution for 11-3(x+4)+5=-3(x+4)+16 equation: 



11-3(x+4)+5=-3(x+4)+16

We move all terms to the left:

11-3(x+4)+5-(-3(x+4)+16)=0

We add all the numbers together, and all the variables

-3(x+4)-(-3(x+4)+16)+16=0

We multiply parentheses

-3x-(-3(x+4)+16)-12+16=0



We calculate terms in parentheses: -(-3(x+4)+16), so:

-3(x+4)+16

We multiply parentheses

-3x-12+16

We add all the numbers together, and all the variables

-3x+4

Back to the equation:

-(-3x+4)



We add all the numbers together, and all the variables

-3x-(-3x+4)+4=0

We get rid of parentheses

-3x+3x-4+4=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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