11-48=4(x-3)-5

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Solution for 11-48=4(x-3)-5 equation: 



11-48=4(x-3)-5

We move all terms to the left:

11-48-(4(x-3)-5)=0

We add all the numbers together, and all the variables

-(4(x-3)-5)-37=0



We calculate terms in parentheses: -(4(x-3)-5), so:

4(x-3)-5

We multiply parentheses

4x-12-5

We add all the numbers together, and all the variables

4x-17

Back to the equation:

-(4x-17)



We get rid of parentheses

-4x+17-37=0

We add all the numbers together, and all the variables

-4x-20=0

We move all terms containing x to the left, all other terms to the right

-4x=20

x=20/-4

x=-5

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