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11-7(x+2)=5(x-3)
We move all terms to the left:
11-7(x+2)-(5(x-3))=0
We multiply parentheses
-7x-(5(x-3))-14+11=0
We calculate terms in parentheses: -(5(x-3)), so:We add all the numbers together, and all the variables
5(x-3)
We multiply parentheses
5x-15
Back to the equation:
-(5x-15)
-7x-(5x-15)-3=0
We get rid of parentheses
-7x-5x+15-3=0
We add all the numbers together, and all the variables
-12x+12=0
We move all terms containing x to the left, all other terms to the right
-12x=-12
x=-12/-12
x=1
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