11-7(z-1)+9=3(z+1)

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Solution for 11-7(z-1)+9=3(z+1) equation: 



11-7(z-1)+9=3(z+1)

We move all terms to the left:

11-7(z-1)+9-(3(z+1))=0

We add all the numbers together, and all the variables

-7(z-1)-(3(z+1))+20=0

We multiply parentheses

-7z-(3(z+1))+7+20=0



We calculate terms in parentheses: -(3(z+1)), so:

3(z+1)

We multiply parentheses

3z+3

Back to the equation:

-(3z+3)



We add all the numbers together, and all the variables

-7z-(3z+3)+27=0

We get rid of parentheses

-7z-3z-3+27=0

We add all the numbers together, and all the variables

-10z+24=0

We move all terms containing z to the left, all other terms to the right

-10z=-24

z=-24/-10

z=2+2/5

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