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11-x(2)=-3
We move all terms to the left:
11-x(2)-(-3)=0
We add all the numbers together, and all the variables
-1x^2+14=0
a = -1; b = 0; c = +14;
Δ = b2-4ac
Δ = 02-4·(-1)·14
Δ = 56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{56}=\sqrt{4*14}=\sqrt{4}*\sqrt{14}=2\sqrt{14}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{14}}{2*-1}=\frac{0-2\sqrt{14}}{-2} =-\frac{2\sqrt{14}}{-2} =-\frac{\sqrt{14}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{14}}{2*-1}=\frac{0+2\sqrt{14}}{-2} =\frac{2\sqrt{14}}{-2} =\frac{\sqrt{14}}{-1} $
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