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11-x=3(x-7)+12x
We move all terms to the left:
11-x-(3(x-7)+12x)=0
We add all the numbers together, and all the variables
-1x-(3(x-7)+12x)+11=0
We calculate terms in parentheses: -(3(x-7)+12x), so:We get rid of parentheses
3(x-7)+12x
We add all the numbers together, and all the variables
12x+3(x-7)
We multiply parentheses
12x+3x-21
We add all the numbers together, and all the variables
15x-21
Back to the equation:
-(15x-21)
-1x-15x+21+11=0
We add all the numbers together, and all the variables
-16x+32=0
We move all terms containing x to the left, all other terms to the right
-16x=-32
x=-32/-16
x=+2
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